#define _USE_MATH_DEFINES
#include<iostream>
#include<string>
#include<cmath>
#include<queue>
#include<map>
#include<set>
#include<list>
#include<iomanip>
#include<vector>
#include<random>
#include<functional>
#include<algorithm>
#include<cstdio>
#include<unordered_map>
using namespace std;
//---------------------------------------------------
//ライブラリゾーン！！！！
typedef long long ll;
typedef long double ld;
#define str string
#define rep(i,j) for(ll i=0;i<(long long)(j);i++)
const ll Mod = 1000000007;
const ll gosenchou = 5000000000000000;
short gh[2][4] = { { 0,0,-1,1 },{ -1,1,0,0 } };
struct P {
ll pos, cost;
};
bool operator<(P a, P b) { return a.cost < b.cost; }
bool operator>(P a, P b) { return a.cost > b.cost; }
struct B {//隣接リスト表現
ll to;
ld cost;
};
struct E {//辺の情報を入れる変数
ll from, to, cost;
};
bool operator<(E a, E b) {
return a.cost < b.cost;
}
struct H {
ll x, y, h;
};
bool operator<(H a, H b) {
if (a.x != b.x) return a.x < b.x;
return a.y < b.y;
}
bool operator>(H a, H b) {
if (a.x != b.x) return a.x > b.x;
return a.y > b.y;
}
bool operator==(H a, H b) {
return a.x == b.x&&a.y == b.y;
}
bool operator!=(H a, H b) {
return a.x != b.x || a.y != b.y;
}
ll gcm(ll i, ll j) {//最大公約数
if (i > j) swap(i, j);
if (i == 0) return j;
return gcm(j%i, i);
}
ld rad(H a, H b) {
return sqrt(pow(a.x - b.x, 2.0) + pow(a.y - b.y, 2.0));
}//rad＝座標上の2点間の距離
ll ari(ll a, ll b, ll c) {
return (a + b)*c / 2;
}//等差数列の和
bool suf(ld a, ld b, ld c, ld d) {
if (b <= c || d <= a) return 0;
return 1;
}//[a,b),[c,d)
ll fact(ll x, ll k) {//最大値、個数
ll sum = 1;
for (int i = 0; i < k; i++)
sum *= (x--);
return sum;
}//階乗(正）
ll mod_pow(ll x, ll n, ll p) {
ll res = 1;
while (n > 0) {
if (n & 1) res = res*x%p;
x = x*x%p;
n >>= 1;
}
return res;
}
#define int long long
const long long inf = 4523372036854775807;
const int iinf = 1500000000;
//----------------------------------------------------
//++++++++++++++++++++++++++++++++++++++++++++++++++++
int a[100001];
signed main() {
int n, sum = 0;
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i];
if (a[i] < i&&a[a[i]] == i) {
sum++;
}
}
cout << sum << endl;
getchar(); getchar();
}